(2x^2+1)(x-2)=0

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Solution for (2x^2+1)(x-2)=0 equation: 


Simplifying
(2x2 + 1)(x + -2) = 0

Reorder the terms:
(1 + 2x2)(x + -2) = 0

Reorder the terms:
(1 + 2x2)(-2 + x) = 0

Multiply (1 + 2x2) * (-2 + x)
(1(-2 + x) + 2x2 * (-2 + x)) = 0
((-2 * 1 + x * 1) + 2x2 * (-2 + x)) = 0
((-2 + 1x) + 2x2 * (-2 + x)) = 0
(-2 + 1x + (-2 * 2x2 + x * 2x2)) = 0
(-2 + 1x + (-4x2 + 2x3)) = 0
(-2 + 1x + -4x2 + 2x3) = 0

Solving
-2 + 1x + -4x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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